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4b^2+8b-77=0
a = 4; b = 8; c = -77;
Δ = b2-4ac
Δ = 82-4·4·(-77)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*4}=\frac{-44}{8} =-5+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*4}=\frac{28}{8} =3+1/2 $
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